In pea plants, purple flowers are dominant to white flowers, and axial flowers are dominant to terminal flowers. If a true-breeding plant with purple, axial flowers is crossed with a true-breeding plant with white, terminal flowers, what proportion of the F2 offspring will have purple, terminal flowers?Multiple choice question.1/23/43/161/49/16
Question
In pea plants, purple flowers are dominant to white flowers, and axial flowers are dominant to terminal flowers. If a true-breeding plant with purple, axial flowers is crossed with a true-breeding plant with white, terminal flowers, what proportion of the F2 offspring will have purple, terminal flowers?Multiple choice question.1/23/43/161/49/16
Solution
To answer this question, we first need to understand the basics of Mendelian genetics.
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In pea plants, purple flowers (P) are dominant to white flowers (p), and axial flowers (A) are dominant to terminal flowers (a).
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A true-breeding plant with purple, axial flowers would have the genotype PPAA, and a true-breeding plant with white, terminal flowers would have the genotype ppaa.
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When these two plants are crossed (PpAa x PpAa), the F1 generation will all have the genotype PpAa, meaning they will all have purple, axial flowers because the dominant traits mask the recessive ones.
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In the F2 generation, produced by self-fertilization of F1 plants, we will see a 9:3:3:1 ratio of the four possible phenotypes (purple axial, purple terminal, white axial, white terminal), according to Mendel's law of independent assortment.
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Therefore, the proportion of the F2 offspring that will have purple, terminal flowers is 3 out of 16, or 3/16. So, the correct answer is 3/16.
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