letter countWrite a C program that will analyze a line of text and will print the number of words, the number of consonants, and the number of vowels in the text.Testcase:Input:Programming is fun!Output:3      // Number of words:11   // Number of consonants:5   // Number of vowels:

Here is a simple C program that will analyze a line of text and print the number of words, the number of consonants, and the number of vowels in the text.

#include <stdio.h>
#include <ctype.h>
#include <string.h>

int main() {
    char str[100];
    int i, vowels = 0, consonants = 0, words = 0;

    printf("Enter a string: ");
    fgets(str, sizeof(str), stdin);

    for(i=0; str[i]!='\0'; ++i) {
        if(str[i]==' ' || str[i]=='\n' || str[i]=='\t') {
            words++;
        }
        else if((str[i]>=65 && str[i]<=90) || (str[i]>=97 && str[i]<=122)) {
            switch(tolower(str[i])) {
                case 'a':
                case 'e':
                case 'i':
                case 'o':
                case 'u':
                    vowels++;
                    break;
                default:
                    consonants++;
            }
        }
    }

    printf("Number of words: %d\n", words);
    printf("Number of vowels: %d\n", vowels);
    printf("Number of consonants: %d\n", consonants);

    return 0;
}

This program works by iterating over each character in the input string. If the character is a space, newline, or tab, it increments the word count. If the character is a letter, it checks whether it's a vowel or a consonant by converting it to lowercase and using a switch statement. If it's a vowel, it increments the vowel count; otherwise, it increments the consonant count.