The vapor pressure of solid iodine at 25°C is 1.42torr. Calculate the vapor pressure in mmHg and atm. Round each of your answers to 3 significant digits.mmHgatm

The vapor pressure of solid iodine at 25°C is given as 1.42 torr.

1. Conversion from torr to mmHg: The conversion factor between torr and mmHg is 1, meaning 1 torr = 1 mmHg. Therefore, the vapor pressure in mmHg is also 1.42 mmHg.

2. Conversion from torr to atm: The conversion factor between torr and atm is approximately 0.00132, meaning 1 torr = 0.00132 atm. Therefore, to convert the vapor pressure to atm, we multiply the given pressure in torr by the conversion factor:

   (1.42 torr) * (0.00132 atm/1 torr) = 0.00187 atm

So, the vapor pressure of solid iodine at 25°C is 1.42 mmHg and 0.00187 atm.

The vapor pressure of solid iodine at 25°C is given as 1.42 torr.

1. Conversion from torr to mmHg: The conversion factor between torr and mmHg is 1, meaning 1 torr = 1 mmHg. Therefore, the vapor pressure in mmHg is also 1.42 mmHg.

2. Conversion from torr to atm: The conversion factor between torr and atm is approximately 0.00132, meaning 1 torr = 0.00132 atm. Therefore, to convert the vapor pressure to atm, we multiply the given pressure in torr by the conversion factor.

   1.42 torr * 0.00132 atm/torr = 0.0018744 atm

Rounding to three significant digits, the vapor pressure in atm is 0.00187 atm.