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What is the output of the following code?char str[] = "hello";printf("%d\n", sizeof(str));

Question

What is the output of the following code?char str[] = "hello";printf("%d\n", sizeof(str));

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Solution

The output of the code will be 6.

Here's the step by step explanation:

  1. The sizeof operator in C returns the amount of memory allocated to the variable or data type.

  2. In this case, str is a character array initialized with the string "hello".

  3. In C, strings are null-terminated, which means a '\0' character is automatically added at the end of the string by the compiler.

  4. So, the size of str is the sum of the sizes of the individual characters 'h', 'e', 'l', 'l', 'o', and the null character '\0'.

  5. Since the size of a char in C is 1 byte, the total size of str is 6 bytes.

Therefore, the output of the code is 6.

This problem has been solved

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