White light consists of wavelengths from 400 nm to 700 nm. What will be the wavelength range seen, When white light is passed through glass of refractive index1.55
Question
White light consists of wavelengths from 400 nm to 700 nm. What will be the wavelength range seen, When white light is passed through glass of refractive index1.55
Solution
The refractive index of a medium is the ratio of the speed of light in vacuum to the speed of light in the medium. It is given by the formula:
n = c/v
where: n is the refractive index, c is the speed of light in vacuum, and v is the speed of light in the medium.
When light passes from one medium to another, its speed changes, which can cause the light to bend. This bending of light is called refraction. The amount of bending depends on the refractive indices of the two media and the angle of incidence of the light.
The refractive index can also affect the wavelength of light. The wavelength of light in a medium is given by the formula:
λ = λ0/n
where: λ is the wavelength of light in the medium, λ0 is the wavelength of light in vacuum, and n is the refractive index of the medium.
Given that the refractive index of the glass is 1.55 and the wavelength range of white light is 400 nm to 700 nm, we can calculate the wavelength range of light in the glass.
For the lower limit of the range:
λ1 = λ01/n = 400 nm / 1.55 = 258 nm
For the upper limit of the range:
λ2 = λ02/n = 700 nm / 1.55 = 452 nm
So, the wavelength range of white light in the glass is 258 nm to 452 nm.
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