Figure Q9 (a) shows a simply supported beam with forces acting atpoints B and point E.Figure Q9 (a)a) For the beam to be in equilibrium, calculate the support reaction force atpoint C and at point D.

For the beam shown below, i) draw a free body diagram, ii) calculate reactions, iii) calculate the internalforces at 2, 7, 10 and 13 m from the left end of the beam iv) sketch the shear axial force, shear forceand bending moment diagrams .

State two conditions for a beam balance to be in equilibrium.

A uniform beam is pivoted at its centre. Two weights are placed on the beam in the positions shown and the beam is balanced by an upward force F.What is the size of F?*1 point

A man raises a joist (length = l) by pulling a rope attached to point B. The centre of mass is located at the centre of the beam and the system is at equilibrium.Variable l αβValue 5 40 25Units [m] [degrees] [degrees]Hints: The reaction does not necessarily act along the joist. This question can be solved without the use of simultaneous equations (Use 3 Force Bodies).Given the information in the table above, determine:1) the angle of the resultant reaction, θ, at point A if at that point the ledge acts as a rough surface.

A uniform 1𝑚 rod of mass 6𝑘𝑔 is being supported horizontally on two knife edgesplaced 20𝑐𝑚 from each end. If a mass of 6𝑘𝑔 is suspended at the 40𝑐𝑚 mark of therod, calculate the reactions at the supports