The hybridization of a molecule can be determined by the types of bonds it forms. In the compound CH3−CH2−C≡H, there are three types of carbon atoms, each with a different hybridization.

1. The carbon atom in the CH3 group is bonded to three hydrogen atoms and one carbon atom. This means it is using four orbitals, so it is sp3 hybridized.

2. The carbon atom in the CH2 group is bonded to two hydrogen atoms and two carbon atoms. This means it is also using four orbitals, so it is also sp3 hybridized.

3. The carbon atom in the C≡H group is bonded to one hydrogen atom and is involved in a triple bond with another carbon atom. This means it is using two orbitals, so it is sp hybridized.

So, the correct answer is A. sp3 for the first two carbon atoms and sp for the last carbon atom.

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The hybridization of a molecule can be determined by the types of bonds it forms. In the compound CH3−CH2−C≡H, there are three types of carbon atoms, each with a different hybridization.

1. The carbon atom in the CH3 group is bonded to three hydrogen atoms and one carbon atom. This means it is using four orbitals, so it is sp3 hybridized.

2. The carbon atom in the CH2 group is bonded to two hydrogen atoms and two carbon atoms. This means it is also using four orbitals, so it is also sp3 hybridized.

3. The carbon atom in the C≡H group is bonded to one hydrogen atom and is involved in a triple bond with another carbon atom. This means it is using two orbitals, so it is sp hybridized.

So, the correct answer is A. sp3 for the first two carbon atoms and sp for the last carbon atom.

Knowee AI · Accepted Answer

The hybridization of a molecule can be determined by the types of bonds it forms. In the compound CH3−CH2−C≡H, there are three types of carbon atoms, each with a different hybridization.

1. The carbon atom in the CH3 group is bonded to three hydrogen atoms and one carbon atom. This means it is using four orbitals, so it is sp3 hybridized.

2. The carbon atom in the CH2 group is bonded to two hydrogen atoms and two carbon atoms. This means it is also using four orbitals, so it is also sp3 hybridized.

3. The carbon atom in the C≡H group is bonded to one hydrogen atom and is involved in a triple bond with another carbon atom. This means it is using two orbitals, so it is sp hybridized.

So, the correct answer is A. sp3 for the first two carbon atoms and sp for the last carbon atom.

The hybridization in the compound CH3−CH2−C≡H𝐶𝐻3−𝐶𝐻2−𝐶≡𝐻 isA. sp33 and spB. spC. sp22D. sp33 and sp2

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