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What is the percentage increase in the number of bits processed as a result of increasing the sampling rate from 44 kHz to 128 kHz? Express your answer to the nearest percent.

Question

What is the percentage increase in the number of bits processed as a result of increasing the sampling rate from 44 kHz to 128 kHz? Express your answer to the nearest percent.

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Solution 1

To calculate the percentage increase, you first need to determine the difference between the two values. Then, divide this difference by the original value and multiply by 100 to get the percentage increase.

Here are the steps:

  1. Find the difference between the two sampling rates: 128 kHz - 44 kHz = 84 kHz
  2. Divide this difference by the original value: 84 kHz / 44 kHz = 1.909
  3. Multiply by 100 to get the percentage increase: 1.909 * 100 = 190.9%

So, the percentage increase in the number of bits processed as a result of increasing the sampling rate from 44 kHz to 128 kHz is approximately 191% when rounded to the nearest percent.

This problem has been solved

Solution 2

To calculate the percentage increase in the number of bits processed due to the increase in sampling rate, we first need to understand the relationship between the two. The number of bits processed is directly proportional to the sampling rate. This means that if the sampling rate increases, the number of bits processed also increases and vice versa.

Here are the steps to calculate the percentage increase:

  1. First, find the difference between the new sampling rate (128 kHz) and the old sampling rate (44 kHz). This can be done by subtracting the old rate from the new rate.

    Difference = New rate - Old rate Difference = 128 kHz - 44 kHz Difference = 84 kHz

  2. Next, divide the difference by the old rate to find the rate of increase.

    Rate of increase = Difference / Old rate Rate of increase = 84 kHz / 44 kHz Rate of increase = 1.909

  3. Finally, multiply the rate of increase by 100 to convert it to a percentage.

    Percentage increase = Rate of increase x 100 Percentage increase = 1.909 x 100 Percentage increase = 190.9%

So, the percentage increase in the number of bits processed as a result of increasing the sampling rate from 44 kHz to 128 kHz is approximately 191% when rounded to the nearest percent.

This problem has been solved

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