Which of the following is not correct?a.ixj=kb.Jxk=-ic.jxi=-kd.i.i=1

The raising (J+) and lowering (J_) operators are defined by J+=JX+ iJy and J_ = JX- iJy.Read the following passage to answer the given questions based on it. Choose the correct options. (Marks: 1)What would be [Jz, J+]OPTIONS ±hJ+ ±hJ- ±hJ ±hJx

If i2 = -1 and if a is a positive integer, which of the following must be equal to ia ?

Which of the following is correct regarding the ion shown below?Group of answer choices

Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAConsider the following expression:jk3k−1+2j2𝑗𝑘3𝑘−1+2𝑗2For which value of k𝑘 is the expression undefined?Answer:The expression is undefined when k=𝑘= .2 attempts remainingHelp! How should I type my answer?Evaluate the expression when j=−2𝑗=−2 and k=−1𝑘=−1, without using a calculator.Here is the expression again:jk3k−1+2j2𝑗𝑘3𝑘−1+2𝑗2INSTRUCTION: Choose the correct option to show the working out, then type in the final answer at the end.Answer:=(−1)(−2)3(−2)−1+2(−1)2(−1)(−8)−3+2(1)(−1)(−2)3(−2)−1+2(−1)2=(−1)(−8)−3+2(1)=(−2)(−1)3(−1)−1+(2)(−2)2(−2)(−1)1+2(−4)(−2)(−1)3(−1)−1+(2)(−2)2=(−2)(−1)1+2(−4)=(−2)(−1)3(−1)−1+2(−2)2(−2)(−1)−2+2(4)(−2)(−1)3(−1)−1+2(−2)2=(−2)(−1)−2+2(4)=(−2)(−13)(−1)−1+2(−22)(−2)(−3)−2+16(−2)(−13)(−1)−1+2(−22)=(−2)(−3)−2+16Therefore the value of the expression when j=−2𝑗=−2 and k=−1𝑘=−1 is .

he raising (J+) and lowering (J_) operators are defined by J+=JX+ iJy and J_ = JX- iJy.Read the following passage to answer the given questions based on it. Choose the correct options. (Marks: 1)What would be [Jx, J ±]?OPTIONS ±ħJz ±ħJ ±ħJy ±iħJz