A sound wave in helium has an intensity of 1.00 × 10−3 W/m2. The density of helium is 0.179 kg/m3 and the speed of sound in helium is 965 m/s. The pressure amplitude of the sound wave is
Question
A sound wave in helium has an intensity of 1.00 × 10−3 W/m2. The density of helium is 0.179 kg/m3 and the speed of sound in helium is 965 m/s. The pressure amplitude of the sound wave is
Solution
The pressure amplitude (P) of a sound wave can be calculated using the formula:
P = sqrt(2 * ρ * v * I)
where: ρ is the density of the medium through which the sound wave is travelling, v is the speed of sound in that medium, and I is the intensity of the sound wave.
In this case, the density of helium (ρ) is 0.179 kg/m^3, the speed of sound in helium (v) is 965 m/s, and the intensity of the sound wave (I) is 1.00 × 10^-3 W/m^2.
Substituting these values into the formula gives:
P = sqrt(2 * 0.179 kg/m^3 * 965 m/s * 1.00 × 10^-3 W/m^2)
Calculating the above expression will give you the pressure amplitude of the sound wave in helium.
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