2(3z+5)>6z−13
Solution
Sure, let's solve the inequality step by step:
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Distribute the 2 on the left side of the inequality: 23z + 25 > 6z - 13, which simplifies to 6z + 10 > 6z - 13.
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Now, let's get all the z terms on one side and the constants on the other. We can subtract 6z from both sides to get: 10 > -13.
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This is a true statement, which means the original inequality is true for all values of z.
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