The correct IUPAC name for the alkane is 2-bromo-3-chloro-2,4-dimethylbutane.

Here's the step-by-step process:

1. Identify the longest carbon chain in the molecule. In this case, it's a butane, which is a 4-carbon chain.

2. Identify the substituents (atoms or groups of atoms attached to the main chain). Here, we have two methyl groups, one bromo group, and one chloro group.

3. Number the carbon atoms in the main chain starting from the end that gives the substituents the lowest possible numbers. In this case, we start numbering from the end closest to the bromo and chloro groups.

4. Assign a number to each substituent according to its position on the chain. Here, the bromo group is on the 2nd carbon, the chloro group is on the 3rd carbon, and the methyl groups are on the 2nd and 4th carbons.

5. Write the name as a single word, using hyphens to separate numbers and commas to separate multiple numbers. The substituents are listed in alphabetical order (bromo before chloro before methyl). So, the correct name is 2-bromo-3-chloro-2,4-dimethylbutane.

Question

The correct IUPAC name for the alkane is 2-bromo-3-chloro-2,4-dimethylbutane.

Here's the step-by-step process:

1. Identify the longest carbon chain in the molecule. In this case, it's a butane, which is a 4-carbon chain.

2. Identify the substituents (atoms or groups of atoms attached to the main chain). Here, we have two methyl groups, one bromo group, and one chloro group.

3. Number the carbon atoms in the main chain starting from the end that gives the substituents the lowest possible numbers. In this case, we start numbering from the end closest to the bromo and chloro groups.

4. Assign a number to each substituent according to its position on the chain. Here, the bromo group is on the 2nd carbon, the chloro group is on the 3rd carbon, and the methyl groups are on the 2nd and 4th carbons.

5. Write the name as a single word, using hyphens to separate numbers and commas to separate multiple numbers. The substituents are listed in alphabetical order (bromo before chloro before methyl). So, the correct name is 2-bromo-3-chloro-2,4-dimethylbutane.

Knowee AI · Accepted Answer

The correct IUPAC name for the alkane is 2-bromo-3-chloro-2,4-dimethylbutane.

Here's the step-by-step process:

1. Identify the longest carbon chain in the molecule. In this case, it's a butane, which is a 4-carbon chain.

2. Identify the substituents (atoms or groups of atoms attached to the main chain). Here, we have two methyl groups, one bromo group, and one chloro group.

3. Number the carbon atoms in the main chain starting from the end that gives the substituents the lowest possible numbers. In this case, we start numbering from the end closest to the bromo and chloro groups.

4. Assign a number to each substituent according to its position on the chain. Here, the bromo group is on the 2nd carbon, the chloro group is on the 3rd carbon, and the methyl groups are on the 2nd and 4th carbons.

5. Write the name as a single word, using hyphens to separate numbers and commas to separate multiple numbers. The substituents are listed in alphabetical order (bromo before chloro before methyl). So, the correct name is 2-bromo-3-chloro-2,4-dimethylbutane.

3-bromo-2-chloro-1,3-dimethylbutane is the wrong name of an alkane. Suggest the correct IUPAC name of the alkane.*1 point2-bromo-3-chloro-2,4-dimethylbutane3-bromo-2-chloro-1,2-dimethylbutane2-bromo-3-chloro-2-methylpentane4-bromo-3-chloro-4-methylpentane

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