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In triangles MNO and PQR, angles M and P each have measure 60 ∘ , MN=15, and PQ=45. Which additional piece of information is sufficient to prove that triangle MNO is similar to triangle PQR?AMO=9 and PR=27BMO=9 and PR=36CThe measure of angles N and Q are 120 ∘ and 120 ∘ , respectively.

Question

In triangles MNO and PQR, angles M and P each have measure 60 ∘ , MN=15, and PQ=45. Which additional piece of information is sufficient to prove that triangle MNO is similar to triangle PQR?AMO=9 and PR=27BMO=9 and PR=36CThe measure of angles N and Q are 120 ∘ and 120 ∘ , respectively.

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Solution

To prove that two triangles are similar, we need to show that their corresponding angles are equal and their corresponding sides are proportional.

We already know that angles M and P are equal (both 60 degrees).

Option A: If AMO=9 and PR=27, we don't have enough information because these are not corresponding sides in the triangles.

Option B: If MO=9 and PR=36, we still don't have enough information because these are not corresponding sides in the triangles.

Option C: If the measure of angles N and Q are 120 degrees, then we have enough information to prove the triangles are similar. This is because we now know that two sets of corresponding angles (M and P, N and Q) are equal.

So, the additional piece of information that is sufficient to prove that triangle MNO is similar to triangle PQR is that the measure of angles N and Q are 120 degrees each.

This problem has been solved

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