A wire, bent as shown is immersed in a uniform magneticfield B = 1 T directed to the right. The horizontal segments are1 m long while the diagonal segment is p2 m long. Current I =1 A flows in the direction shown. What is the net force on thewire?

The force on a current-carrying wire in a magnetic field is given by the equation F = I * L * B * sin(θ), where I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the direction of the current and the direction of the magnetic field.

1. Calculate the force on the horizontal segments: The angle between the direction of the current and the direction of the magnetic field is 90 degrees for the horizontal segments. So, sin(90) = 1. Therefore, the force on each horizontal segment is F = I * L * B * sin(90) = 1 A * 1 m * 1 T * 1 = 1 N. Since the forces on the two horizontal segments are in opposite directions, they cancel each other out.

2. Calculate the force on the diagonal segment: The angle between the direction of the current and the direction of the magnetic field is 45 degrees for the diagonal segment. So, sin(45) = √2/2. Therefore, the force on the diagonal segment is F = I * L * B * sin(45) = 1 A * √2 m * 1 T * √2/2 = 1 N.

3. Calculate the net force on the wire: The net force on the wire is the sum of the forces on all segments. Since the forces on the horizontal segments cancel each other out, the net force on the wire is just the force on the diagonal segment, which is 1 N.