Q4: Consider these three statements: char S[10]="trouble"; char *t=S+2; *(t+3) = '\0';The best description of the situation after these three statements is that:Array S now contains the string "troub"Array S now contains the string "tro"Array S now contains the string "tro\0uble"Array S still contains the string "trouble"The code will not compile correctly, and hence cannot be executed
Question
Q4: Consider these three statements: char S[10]="trouble"; char *t=S+2; *(t+3) = '\0';The best description of the situation after these three statements is that:Array S now contains the string "troub"Array S now contains the string "tro"Array S now contains the string "tro\0uble"Array S still contains the string "trouble"The code will not compile correctly, and hence cannot be executed
Solution
The best description of the situation after these three statements is that: Array S now contains the string "tro".
Explanation:
In the first statement, the array S is initialized with the string "trouble".
In the second statement, a pointer t is declared and it points to the third character of the string S (since array indexing starts from 0).
In the third statement, the character at the position 3 places after where t points (which is the 'b' in "trouble") is replaced with the null character '\0'.
So, after these three statements, the string in the array S becomes "tro\0uble". However, in C, strings are null-terminated, which means that the null character '\0' marks the end of the string. Therefore, when the string S is printed or used in a context where a string is expected, only the characters before the null character will be considered. So, the string in the array S will be "tro".
Similar Questions
Consider the following two statements: char S[20]="aardvark"; char *p = "baboon"; p = S+2; p[3] = 0;The best description of the situation after these four statements is that:Group of answer choicesThe code can be compiled, but when it is executed it will give a run-time error because pointer p points to restricted memory used to store string constantsThe code will not compile correctly because of type mismatches, and hence cannot be executedPointer p points at the string "rdv"Pointer p points at the string "rdv0rk"Pointer p points at the string "baboo0"
In C++, strings are treated as an array of characters
Consider the following declarations:char a[] = "abhijit";char b[16] = {'a', 'b', 'h', 'i', 'j', 'i', 't'};char *c = "abhijit";char d[16] = "abhijit";Mark the statements as True/False w.r.t. the above.Read each word and number carefully.True False both b and d contain some random data elements of array a[] can not be modified contents of arrays b and c can b modified a points to a constant array, and sayinga[2]= 'x'will cause sgfault c points to a constant string, and sayingc[2] = 'x'will cause a segfault. sizeof(a) and sizeof(c) are 8 bytes b is a string of length 8, with 7 bytes representing 7 characters of "abhijit" and one '\0' byte. b is an array of size 8, with 7 bytes representing 7 characters of "abhijit" and one '\0' byte. sizeof(b) and sizeof(d) are 16 bytes declaration of b is syntactically wrong
Consider these two statements: char v[6]; strcpy(v, "string");The best description of the situation after these two statements is that:Group of answer choicesThe call to strcpy() will corrupt memory and may result in a program run-time error at some later point in the program's executionA run-time array overflow will be detected, and the program will be halted and an error message printedThe call to strcpy() will be truncated, and only "tring" will be copied into vThe call to strcpy() is completely fine, and v will have the desired value of "string"The call to strcpy() will be truncated, and only "strin" will be copied into v
Given1. public class Program{2. static int i = 2;3. public static void main(String[] args) {4. int array[] = new int[i];5. array[1] = 7;6. array[2] = 8;7. System.out.print(array[1]);8. }9. } Which is true?*An Exception will be thrown at the runtime.Compilation fails as we can’t assign int values as the elements of a char array.The output will be 0.The output will be 8.The output will be 7.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.