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A person moves 30 m north and then 20 m towards east and finally 302√ m south-west direction. The displacement of the person from the origin will be10 m along north10 m along south10 m along westzero

Question

A person moves 30 m north and then 20 m towards east and finally 302√ m south-west direction. The displacement of the person from the origin will be10 m along north10 m along south10 m along westzero

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Solution

The person first moves 30 m north, then 20 m east, and finally 30√2 m southwest.

The southwest movement can be broken down into two components: one south and one west, because southwest is a 45 degree angle between south and west.

So, the south component of the southwest movement is 30√2 * cos(45) = 30 m, and the west component is 30√2 * sin(45) = 30 m.

Now, let's add up all the movements:

North-South: 30 m (north) - 30 m (south component of southwest movement) = 0 m

East-West: 20 m (east) - 30 m (west component of southwest movement) = -10 m. The negative sign indicates a westward direction.

So, the total displacement of the person from the origin is 10 m towards the west.

This problem has been solved

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