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In part B of this experiment, you will quantitatively determine the amount of aspirin, phenacetin and caffeine in an "analgesic tablet" by UV-vis absorption spectroscopy.A student is asked to perform the following procedure which is similar to the preparation of the UV-vis absorption sample in part B of PHY6:1.       Place unknown sample ‘X’ in a 200 ml volumetric flask, add 50 ml of water and 10 ml of 0.5 M KOH.  Shake until the tablet breaks up and all crystalline material has dissolved.  Dilute to 200 ml with methanol. 2.       Pipette 1 ml of this solution into a 40 ml volumetric flask and make up to 40 ml with methanol.  A blank should be prepared in the same way, which contains all reagents except the tablet.3.       Record the UV-vis absorption spectrum of this solution over the range 380-220 nm, using the blank solution to set the baselineIf, 6.83 x 10-4 mol/L of aspirin is present in the diluted sample solution used to obtain the UV-vis absorption spectrum, what is the concentration of aspirin in the undiluted stock solution?Undiluted [aspirin] = Answer 1 Question 1 mol/L (Give your answer to 3 significant figures in scientific notation i.e. 1.23E-4).

Question

In part B of this experiment, you will quantitatively determine the amount of aspirin, phenacetin and caffeine in an "analgesic tablet" by UV-vis absorption spectroscopy.A student is asked to perform the following procedure which is similar to the preparation of the UV-vis absorption sample in part B of PHY6:1.       Place unknown sample ‘X’ in a 200 ml volumetric flask, add 50 ml of water and 10 ml of 0.5 M KOH.  Shake until the tablet breaks up and all crystalline material has dissolved.  Dilute to 200 ml with methanol. 2.       Pipette 1 ml of this solution into a 40 ml volumetric flask and make up to 40 ml with methanol.  A blank should be prepared in the same way, which contains all reagents except the tablet.3.       Record the UV-vis absorption spectrum of this solution over the range 380-220 nm, using the blank solution to set the baselineIf, 6.83 x 10-4 mol/L of aspirin is present in the diluted sample solution used to obtain the UV-vis absorption spectrum, what is the concentration of aspirin in the undiluted stock solution?Undiluted [aspirin] = Answer 1 Question 1 mol/L (Give your answer to 3 significant figures in scientific notation i.e. 1.23E-4).

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Solution

To find the concentration of aspirin in the undiluted stock solution, we need to consider the dilution factor.

The initial solution was diluted from 200 ml to 40 ml, which is a dilution factor of 200/40 = 5.

Then, 1 ml of this solution was diluted to 40 ml, which is a dilution factor of 40/1 = 40.

So, the total dilution factor is 5 * 40 = 200.

The concentration of aspirin in the diluted sample solution is 6.83 x 10^-4 mol/L.

Therefore, the concentration of aspirin in the undiluted stock solution is (6.83 x 10^-4 mol/L) * 200 = 1.366 x 10^-1 mol/L.

So, the concentration of aspirin in the undiluted stock solution is 1.37E-1 mol/L (to three significant figures in scientific notation).

This problem has been solved

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