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Eugene sold his tarts to earn allowance during school vacation. The number of $2, $5 and $10-notes she earned were in ratio of 3 : 7 : 5. The notes were worth $2821 altogether. How many $2-notes were there?

Question

Eugene sold his tarts to earn allowance during school vacation. The number of 2,2, 5 and 10notessheearnedwereinratioof3:7:5.Thenoteswereworth10-notes she earned were in ratio of 3 : 7 : 5. The notes were worth 2821 altogether. How many $2-notes were there?

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Solution

Sure, here's how you can solve this problem:

Step 1: Understand the problem Eugene sold tarts and earned money in 2,2, 5, and 10notes.Theratioofthesenotesis3:7:5andthetotalamountofmoneyis10 notes. The ratio of these notes is 3:7:5 and the total amount of money is 2821. We need to find out how many $2 notes there are.

Step 2: Set up the equation Let's denote the common ratio as x. So, the number of 2notesis3x,thenumberof2 notes is 3x, the number of 5 notes is 7x, and the number of $10 notes is 5x. Since we know the total amount of money, we can set up the following equation:

2*(3x) + 5*(7x) + 10*(5x) = 2821

Step 3: Solve the equation Solving the equation gives:

6x + 35x + 50x = 2821 91x = 2821 x = 2821 / 91 x = 31

Step 4: Find the number of 2notesNowthatweknowx,wecanfindoutthenumberof2 notes Now that we know x, we can find out the number of 2 notes, which is 3x:

3 * 31 = 93

So, there were 93 $2 notes.

This problem has been solved

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