In a filtration experiment 25cm^3 of a solution of sodium hydroxide containing 8gperlitre was required for complete neutralization of 0.245g of a dibasic acid. Calculate the relative molecular mass of the acid(Na=23.0, O=16, H=1)

Sure, here is the step by step solution:

Step 1: Calculate the concentration of sodium hydroxide (NaOH) solution in mol/L.

Given that the solution contains 8g of NaOH per litre, and the molar mass of NaOH is (23.0 + 16.0 + 1.0) = 40.0 g/mol, the concentration of NaOH is (8/40) = 0.2 mol/L.

Step 2: Calculate the volume of NaOH solution in litres.

Given that the volume of the solution is 25 cm^3, convert this to litres by dividing by 1000, so the volume is 0.025 L.

Step 3: Calculate the number of moles of NaOH.

The number of moles of NaOH is given by the formula: moles = concentration x volume. So, the number of moles of NaOH is (0.2 mol/L x 0.025 L) = 0.005 mol.

Step 4: Calculate the number of moles of the dibasic acid.

Since the acid is dibasic, it means that one molecule of the acid reacts with two molecules of NaOH. Therefore, the number of moles of the acid is half the number of moles of NaOH, which is (0.005 mol / 2) = 0.0025 mol.

Step 5: Calculate the relative molecular mass (Mr) of the acid.

The relative molecular mass of the acid is given by the formula: Mr = mass / moles. Given that the mass of the acid is 0.245 g, the Mr of the acid is (0.245 g / 0.0025 mol) = 98 g/mol.

So, the relative molecular mass of the acid is 98 g/mol.