elect the correct answerTwo cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options240300330270
Question
elect the correct answerTwo cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options240300330270
Solution
Let's solve this step by step:
Step 1: Let's denote the distance between the two cities as D (in km), the speed of car A as Sa (in km/hr), the speed of car B as Sb (in km/hr), the time taken by car A as Ta (in hours), and the time taken by car B as Tb (in hours).
From the problem, we know that: Sa = 60 km/hr Sb = 108 km/hr Ta = Tb + 2 hours
Step 2: We know that distance = speed * time. So, we can write two equations as follows: D = Sa * Ta D = Sb * Tb
Step 3: Since both equations are equal to D, we can set them equal to each other: Sa * Ta = Sb * Tb
Step 4: Substitute the known values into the equation: 60 * (Tb + 2) = 108 * Tb
Step 5: Solve for Tb: 60Tb + 120 = 108Tb 120 = 48Tb Tb = 120 / 48 = 2.5 hours
Step 6: Substitute Tb back into the equation D = Sb * Tb to find the distance: D = 108 * 2.5 = 270 km
So, the distance between the two cities is 270 km.
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