ect the correct answerWhat will be the output of the following Java code? class Codetantra { final public int output(int x, int y) { return 1; } } class Program extends Codetantra { public int output(int x, int y) { return 2; } } public class result { public static void main(String args[]) { Program object = new Program(); System.out.print("y is " + y.output(0, 1)); } }
Question
ect the correct answerWhat will be the output of the following Java code? class Codetantra { final public int output(int x, int y) { return 1; } } class Program extends Codetantra { public int output(int x, int y) { return 2; } } public class result { public static void main(String args[]) { Program object = new Program(); System.out.print("y is " + y.output(0, 1)); } }
Solution
The code will not compile. The method output(int x, int y) in the Program class is attempting to override the same method in the Codetantra class. However, the method in the Codetantra class is declared as final, which means it cannot be overridden. Therefore, a compile-time error will occur.
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