Write the equation of the parabola that passes through the points (–2,0), (–3,18), and (–1,0).Write your answer in the form y=a(x–p)(x–q), where a, p, and q are integers, decimals, or simplified fractions.
Question
Write the equation of the parabola that passes through the points (–2,0), (–3,18), and (–1,0).Write your answer in the form y=a(x–p)(x–q), where a, p, and q are integers, decimals, or simplified fractions.
Solution
To find the equation of the parabola that passes through the points (-2,0), (-3,18), and (-1,0), we can use the form y=a(x–p)(x–q), where a, p, and q are the x-intercepts of the parabola.
From the given points, we can see that the x-intercepts are -2 and -1 (the points where y=0). So, p=-2 and q=-1.
Now, we need to find the value of a. We can use the point (-3,18) to find a. Substituting x=-3 and y=18 into the equation, we get:
18=a(-3-(-2))(-3-(-1))
Solving this equation gives a=18.
So, the equation of the parabola is y=18(x+2)(x+1).
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