The problem states that the average of 9z numbers is 12z. This means that the total sum of all the numbers is 9z * 12z = 108z^2.

Then, it says that 4z-2 is subtracted from each number. Since there are 9z numbers, the total amount subtracted from the sum is (4z-2) * 9z = 36z^2 - 18z.

So, the new total sum is 108z^2 - (36z^2 - 18z) = 72z^2 + 18z.

Finally, to find the new average, we divide this new sum by the total number of numbers, which is 9z. So, the new average is (72z^2 + 18z) / 9z = 8z + 2.

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The problem states that the average of 9z numbers is 12z. This means that the total sum of all the numbers is 9z * 12z = 108z^2.

Then, it says that 4z-2 is subtracted from each number. Since there are 9z numbers, the total amount subtracted from the sum is (4z-2) * 9z = 36z^2 - 18z.

So, the new total sum is 108z^2 - (36z^2 - 18z) = 72z^2 + 18z.

Finally, to find the new average, we divide this new sum by the total number of numbers, which is 9z. So, the new average is (72z^2 + 18z) / 9z = 8z + 2.

Knowee AI · Accepted Answer

The problem states that the average of 9z numbers is 12z. This means that the total sum of all the numbers is 9z * 12z = 108z^2.

Then, it says that 4z-2 is subtracted from each number. Since there are 9z numbers, the total amount subtracted from the sum is (4z-2) * 9z = 36z^2 - 18z.

So, the new total sum is 108z^2 - (36z^2 - 18z) = 72z^2 + 18z.

Finally, to find the new average, we divide this new sum by the total number of numbers, which is 9z. So, the new average is (72z^2 + 18z) / 9z = 8z + 2.

The average of 9z numbers is 12z. If 4z-2 is subtracted from each, then the new average is?

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