What will be the output of the following C code?#include <stdio.h> void main() {  m();  m(); } void m() { static int x = 5; x++; printf("%d", x); }6 76 65 55 6

The output of the given C code will be "6 7".

Here's the step by step explanation:

1. The main function is called first. Inside the main function, the function m() is called twice.

2. The function m() has a static integer variable x which is initialized to 5. The keyword 'static' means that the variable retains its value between function calls.

3. When m() is called the first time, x is incremented by 1 (from 5 to 6) and then printed. So, "6" is printed.

4. When m() is called the second time, x is again incremented by 1 (from 6 to 7) and then printed. So, "7" is printed.

5. Therefore, the output of the program is "6 7".