Na+ has completely filled K and L shells. Explain

Na+ has completely filled K and L shells.

To explain this, we need to understand the electronic configuration of sodium (Na) and how it fills its electron shells.

The atomic number of sodium is 11, which means it has 11 electrons. The electronic configuration of sodium is 2-8-1, which indicates that it has two electrons in the first shell (K shell), eight electrons in the second shell (L shell), and one electron in the third shell (M shell).

However, when sodium loses one electron to form a sodium ion (Na+), it becomes positively charged. This happens because the loss of one electron leaves behind 10 electrons, which is the same as the electronic configuration of neon (2-8).

Now, let's focus on the filled shells. The K shell can hold a maximum of 2 electrons, and in the case of sodium, it has 2 electrons in the K shell. Therefore, the K shell is completely filled.

Moving on to the L shell, it can hold a maximum of 8 electrons. In the case of sodium, it originally had 8 electrons in the L shell. However, when sodium loses one electron to form Na+, it now has only 7 electrons in the L shell. This means that the L shell is not completely filled.

In conclusion, Na+ has completely filled K and L shells. The K shell is filled with 2 electrons, and the L shell is filled with 8 electrons, even though it originally had 8 electrons and lost one to form Na+.