he following Message "B C C A B B D D A E C C B B A E D D C C", is given. Use Huffman algorithm to find the total size of the message 1 point43 bits45 bits40 bits41 bits

To solve this problem, we need to follow the steps of Huffman's algorithm:

1. First, we need to calculate the frequency of each character in the message:

   A: 4 B: 5 C: 6 D: 4 E: 2

2. Then, we create a priority queue (or a min-heap) and insert all characters along with their frequencies. The character with the lowest frequency has the highest priority:

   E: 2 A: 4 D: 4 B: 5 C: 6

3. We remove two nodes with the highest priority (lowest frequency) from the queue and create a new node. We add the frequencies of these two nodes and insert this new node into the queue. We repeat this step until there is only one node left in the queue.

   AD: 8 B: 5 C: 6 EAD: 10 BC: 11 EADBC: 21

4. The last node is the root of our Huffman tree. We assign codes to characters by traversing the tree. If we go to the left child, we add '0' to the code. If we go to the right child, we add '1' to the code.

   A: 100 B: 01 C: 00 D: 101 E: 110

5. Finally, we calculate the total size of the message. We multiply the frequency of each character by the length of its code and sum up these values:

   A: 4 * 3 = 12 bits B: 5 * 2 = 10 bits C: 6 * 2 = 12 bits D: 4 * 3 = 12 bits E: 2 * 3 = 6 bits

   Total size = 12 + 10 + 12 + 12 + 6 = 52 bits

So, none of the options provided are correct. The total size of the message is 52 bits.