The atomic radius (r) of a Body-Centered Cubic (BCC) structure can be found using the formula for the diagonal of the cube, which is √3*a, where a is the edge length of the cube.

In a BCC structure, the diagonal of the cube is made up of 4 radii (2 atomic radii from the center atom and 1 atomic radius from each of the corner atoms).

So, we can set up the equation as follows:

√3*a = 4r

Solving for r (the atomic radius), we get:

r = a√3/4

So, the atomic radius of a BCC structure is a√3/4. Therefore, the correct answer is (a).

Question

The atomic radius (r) of a Body-Centered Cubic (BCC) structure can be found using the formula for the diagonal of the cube, which is √3*a, where a is the edge length of the cube.

In a BCC structure, the diagonal of the cube is made up of 4 radii (2 atomic radii from the center atom and 1 atomic radius from each of the corner atoms).

So, we can set up the equation as follows:

√3*a = 4r

Solving for r (the atomic radius), we get:

r = a√3/4

So, the atomic radius of a BCC structure is a√3/4. Therefore, the correct answer is (a).

Knowee AI · Accepted Answer

The atomic radius (r) of a Body-Centered Cubic (BCC) structure can be found using the formula for the diagonal of the cube, which is √3*a, where a is the edge length of the cube.

In a BCC structure, the diagonal of the cube is made up of 4 radii (2 atomic radii from the center atom and 1 atomic radius from each of the corner atoms).

So, we can set up the equation as follows:

√3*a = 4r

Solving for r (the atomic radius), we get:

r = a√3/4

So, the atomic radius of a BCC structure is a√3/4. Therefore, the correct answer is (a).

The atomic radius of BCC structure is……………a.a√3/4b.a√/4c.None of thesed.a/2

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