What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}

The code you've written is in C language and it's trying to assign a value to a pointer without initializing it first. This is undefined behavior in C.

Here's a step by step explanation:

1. int *ptr; This line declares a pointer to an integer. However, it doesn't initialize the pointer, so it points to some arbitrary memory location.

2. *ptr = 98; This line tries to write the value 98 to the memory location that ptr points to. Since ptr was never initialized, this is undefined behavior. The program could crash, or it could overwrite some other data in your program, or it could appear to work correctly. It's unpredictable.

3. printf("%d\n", *ptr); This line tries to print the value at the memory location that ptr points to. Again, since ptr was never initialized, this is undefined behavior.

4. return (0); This line returns 0 from main, indicating that the program completed successfully. However, if the program didn't crash earlier, it's purely by luck.

In conclusion, you should never write to or read from an uninitialized pointer. Always make sure your pointers are initialized to a valid memory location before you use them.