Sure, here is a simple function in C++ that does exactly that: ```cpp #include using namespace std; void traverse_back(int* ptr, int n) { for(int i = 0; i

Question

Sure, here is a simple function in C++ that does exactly that:

```cpp
#include<iostream>
using namespace std;

void traverse_back(int* ptr, int n) {
    for(int i = 0; i < n; i++) {
        cout << *(ptr - i) << " ";
    }
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int n = sizeof(arr)/sizeof(arr[0]);
    traverse_back((arr + n - 1), n);
    return 0;
}
```

Here's how it works:

1. The function `traverse_back()` takes a pointer to the last element of the array and the number of elements in the array as arguments.

2. It then enters a loop that runs `n` times, where `n` is the number of elements in the array.

3. Inside the loop, it uses the pointer arithmetic to access the elements of the array in reverse order. The expression `*(ptr - i)` gives the `i`th element from the end of the array.

4. It prints the value of each element.

5. In the `main()` function, we calculate the number of elements in the array using `sizeof(arr)/sizeof(arr[0])` and pass the address of the last element of the array `(arr + n - 1)` to the `traverse_back()` function.

Knowee AI · Accepted Answer

Sure, here is a simple function in C++ that does exactly that:

```cpp
#include<iostream>
using namespace std;

void traverse_back(int* ptr, int n) {
    for(int i = 0; i < n; i++) {
        cout << *(ptr - i) << " ";
    }
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int n = sizeof(arr)/sizeof(arr[0]);
    traverse_back((arr + n - 1), n);
    return 0;
}
```

Here's how it works:

1. The function `traverse_back()` takes a pointer to the last element of the array and the number of elements in the array as arguments.

2. It then enters a loop that runs `n` times, where `n` is the number of elements in the array.

3. Inside the loop, it uses the pointer arithmetic to access the elements of the array in reverse order. The expression `*(ptr - i)` gives the `i`th element from the end of the array.

4. It prints the value of each element.

5. In the `main()` function, we calculate the number of elements in the array using `sizeof(arr)/sizeof(arr[0])` and pass the address of the last element of the array `(arr + n - 1)` to the `traverse_back()` function.

Given an address of the last element from an integer array and number of elements to a function traverse_back(), do print the value inside array from last element to first element without using subscriptoperator([]).

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