The consumption of water by a Water Company satisfies the empirical equation; V= 1.50𝘵 + 0.008𝘵² . Where V is the volume of water in cubic feet and t is the time in months. What is the consumption in 120 𝘥𝘢𝘺𝘴 in units of 𝘭𝘪𝘵𝘳𝘦𝘴? [Assume 1.0 f t³ ∼ 28.32 𝘭𝘪𝘵𝘳𝘦].

The consumption of natural gas by a company satisfiesthe empirical equation where Vis the volume in millions of cubic feet and t the time inmonths. Express this equation in units of cubic feet andseconds. Put the proper units on the coefficients. As-sume a month is 30.0 day

A water tank initially holds 100L of water. It springs a leak so that water leaks out at a rate of𝐹(𝑡)=−3𝑒−0.2𝑡Litres per second, where 𝑡 is the number of seconds since the leak developed.1. Write an equation for the volume 𝑉 of water in the tank at time 𝑡. Simplify your answer.𝑉(𝑡)=

Oil leaked from a tank at a rate of r(t) liters per hour. The rate decreased as time passed, and values of the rate at two hour time intervals are shown in the table. Find lower and upper estimates for the total amount of oil that leaked out.V ≈ L (lower estimate)V ≈ L (upper estimate)t (h) 0 2 4 6 8 10r(t) (L/h) 8.6 7.6 6.7 6.4 5.6 5.3

A power company calculates a person's monthly bill from the number of kilowatt-hours (kWh), x, used.The function 𝑏(𝑥)={0.15𝑥,𝑥≤2000.10(𝑥−200)+30,𝑥>200b(x)={ 0.15x,x≤2000.10(x−200)+30,x>200​ determines the bill.How much is the bill for a person who uses 300 kWh in a month?A.$55B.$40C.$60D.$45

The local water company uses the following function for computing their customers' monthly water bills.C(x)={1.09x+3.116.82x−4007.89if0<x≤700ifx>700𝐶(𝑥)={1.09𝑥+3.11if0<𝑥≤7006.82𝑥−4007.89if𝑥>700, where x is the number of gallons used and C(x)𝐶(𝑥) is the cost in dollars.Step 1 of 3 :  Find limx→700−C(x)lim𝑥→700−⁡𝐶(𝑥).