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Which of the following statements does NOT explain the meaning of the term ‘power’ in physics?The amount of energy transferred per secondThe rate at which energy is transferredThe rate at which work is doneThe total amount of energy which something has2An LED light bulb has a power rating of 6 W.  What does this mean?The bulb will use six ‘units of electricity’ per hourThe bulb must be connected to a 6 V power supplySix joules of energy are transferred to the bulb every secondThe bulb will only light once six joules of energy have been transferred to it3An athlete runs up a flight of stairs in 10 seconds and 16 kJ of energy is transferred to their gravitational potential store.  Calculate their power output.  You may neglect all other energy transfers in answering this question.1.6 W160 W160,000 W1600 W4The output of a mobile phone charger is labelled ‘5 V, 1 A, 5 W’.  How much electrical energy will be supplied by the charger when it runs steadily for ten minutes?50 J3 kJ250 J15 kJ5A car of mass 2000 kg accelerates from rest to 20 m/s in 10 seconds.  Calculate the average power output of its engine.  In answering this question, you may assume that all of the energy which is supplied by the car’s engine is transferred to its kinetic store.4,000 W40,000 W4,000,000 W400,000 W6During a television programme, 180 kJ of energy was transferred to a 100 W television.  How long was the programme?18 seconds1,800 seconds18,000 seconds546 seconds

Question

Which of the following statements does NOT explain the meaning of the term ‘power’ in physics?The amount of energy transferred per secondThe rate at which energy is transferredThe rate at which work is doneThe total amount of energy which something has2An LED light bulb has a power rating of 6 W.  What does this mean?The bulb will use six ‘units of electricity’ per hourThe bulb must be connected to a 6 V power supplySix joules of energy are transferred to the bulb every secondThe bulb will only light once six joules of energy have been transferred to it3An athlete runs up a flight of stairs in 10 seconds and 16 kJ of energy is transferred to their gravitational potential store.  Calculate their power output.  You may neglect all other energy transfers in answering this question.1.6 W160 W160,000 W1600 W4The output of a mobile phone charger is labelled ‘5 V, 1 A, 5 W’.  How much electrical energy will be supplied by the charger when it runs steadily for ten minutes?50 J3 kJ250 J15 kJ5A car of mass 2000 kg accelerates from rest to 20 m/s in 10 seconds.  Calculate the average power output of its engine.  In answering this question, you may assume that all of the energy which is supplied by the car’s engine is transferred to its kinetic store.4,000 W40,000 W4,000,000 W400,000 W6During a television programme, 180 kJ of energy was transferred to a 100 W television.  How long was the programme?18 seconds1,800 seconds18,000 seconds546 seconds

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Solution

Sure, I can help with that. Here are the answers to your questions:

  1. The statement that does NOT explain the meaning of the term ‘power’ in physics is "The total amount of energy which something has". Power in physics is defined as the rate at which work is done or energy is transferred, not the total amount of energy something has.

  2. An LED light bulb with a power rating of 6 W means "Six joules of energy are transferred to the bulb every second".

  3. To calculate the power output of the athlete, we first need to convert the energy from kilojoules to joules (1 kJ = 1000 J), so 16 kJ = 16000 J. Power is energy/time, so the power output is 16000 J / 10 s = 1600 W.

  4. The output of a mobile phone charger is labelled ‘5 V, 1 A, 5 W’. The energy supplied by the charger in ten minutes can be calculated by multiplying the power (in watts) by the time (in seconds). So, 5 W * 600 s = 3000 J, which is 3 kJ.

  5. To calculate the average power output of the car's engine, we first need to calculate the work done, which is the change in kinetic energy. The kinetic energy can be calculated using the formula 1/2 * mass * velocity^2. So, the work done is 1/2 * 2000 kg * (20 m/s)^2 = 400,000 J. The power is then the work done divided by the time, so 400,000 J / 10 s = 40,000 W.

  6. To find out how long the programme was, we need to divide the total energy transferred (in joules) by the power of the television (in watts). So, 180,000 J / 100 W = 1800 seconds.

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