The area of cross section of two connected cylinders are 10 cm2 and 50 cm2 respectively. In order to move up a weight of 100 N placed on the piston of larger area, what force should be applied on the piston of smaller area?
Question
The area of cross section of two connected cylinders are 10 cm2 and 50 cm2 respectively. In order to move up a weight of 100 N placed on the piston of larger area, what force should be applied on the piston of smaller area?
Solution
The problem can be solved using Pascal's principle, which states that when a change in pressure is applied to an enclosed fluid, it is transmitted undiminished to all portions of the fluid and to the walls of its container.
Given: Area of cross section of smaller cylinder (A1) = 10 cm² Area of cross section of larger cylinder (A2) = 50 cm² Weight on the larger cylinder (W) = 100 N
We need to find the force (F) that should be applied on the piston of smaller area.
According to Pascal's principle, the pressure applied on both cylinders should be the same. Pressure is defined as force per unit area. Therefore, we can write:
Pressure on smaller cylinder = Pressure on larger cylinder F/A1 = W/A2
Substituting the given values:
F/10 = 100/50
Solving for F:
F = (100/50) * 10 F = 20 N
Therefore, a force of 20 N should be applied on the piston of the smaller area to move up the weight of 100 N placed on the piston of the larger area.
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