The problem statement is asking to write a program that uses a recursive function. The function, named recursiveFunc, takes an integer input n. Inside the function, a local variable m is initialized to 3. The program should print the value of m before and after each recursive call. The input integer n is obtained from the user in the main function. Here is a step-by-step guide to solve this problem: 1. First, you need to create a main function where you will get the input from the user. 2. Inside the main function, call the recursive function with the input integer. 3. Now, create the recursive function. Inside this function, initialize a local variable m to 3. 4. Print the value of m and the current call number before making the recursive call. 5. Make the recursive call with n-1 if n is greater than 0. 6. After the recursive call, print the value of m and the current call number again. Here is a simple implementation in C++: ```cpp #include using namespace std; void recursiveFunc(int n) { auto m = 3; cout 0) { recursiveFunc(n-1); } cout > n; recursiveFunc(n); return 0; } ``` This program will print the value of m before and after each recursive call from n to 0. The value of m will always be 3 because it is a local variable and gets reinitialized in each function call.

Single File Programming QuestionProblem StatementJessi wants to write a program where a recursive function, recursiveFunc, is called with an input integer n. Inside the function, a local variable m is initialized to 3 using the auto keyword. The program prints the value of m before and after each recursive call. The input integer n is obtained from the user in the main function.Input format :The input consists of an integer n.Output format :The output prints the value of the variable m before and after each recursive call from n to 0:The format for before call: "Before call(x): m" where x is the number of the particular call.The format for after call: "After return(x): m" where x is the number of the particular call.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:1 ≤ n ≤ 10Sample test cases :Input 1 :1Output 1 :Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3Input 2 :5Output 2 :Before call(5): 3Before call(4): 3Before call(3): 3Before call(2): 3Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3After return(2): 3After return(3): 3After return(4): 3After return(5): 3Input 3 :10Output 3 :Before call(10): 3Before call(9): 3Before call(8): 3Before call(7): 3Before call(6): 3Before call(5): 3Before call(4): 3Before call(3): 3Before call(2): 3Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3After return(2): 3After return(3): 3After return(4): 3After return(5): 3After return(6): 3After return(7): 3After return(8): 3After return(9): 3After return(10): 3Note :The program will be evaluated only after the “Submit Code” is clicked.Extra spaces and new line characters in the program output will result in the failure of the test case.

Question

Single File Programming QuestionProblem StatementJessi wants to write a program where a recursive function, recursiveFunc, is called with an input integer n. Inside the function, a local variable m is initialized to 3 using the auto keyword. The program prints the value of m before and after each recursive call. The input integer n is obtained from the user in the main function.Input format :The input consists of an integer n.Output format :The output prints the value of the variable m before and after each recursive call from n to 0:The format for before call: "Before call(x): m" where x is the number of the particular call.The format for after call: "After return(x): m" where x is the number of the particular call.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:1 ≤ n ≤ 10Sample test cases :Input 1 :1Output 1 :Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3Input 2 :5Output 2 :Before call(5): 3Before call(4): 3Before call(3): 3Before call(2): 3Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3After return(2): 3After return(3): 3After return(4): 3After return(5): 3Input 3 :10Output 3 :Before call(10): 3Before call(9): 3Before call(8): 3Before call(7): 3Before call(6): 3Before call(5): 3Before call(4): 3Before call(3): 3Before call(2): 3Before call(1): 3Before call(0): 3After return(0): 3After return(1): 3After return(2): 3After return(3): 3After return(4): 3After return(5): 3After return(6): 3After return(7): 3After return(8): 3After return(9): 3After return(10): 3Note :The program will be evaluated only after the “Submit Code” is clicked.Extra spaces and new line characters in the program output will result in the failure of the test case.

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Solution 1

The problem statement is asking to write a program that uses a recursive function. The function, named recursiveFunc, takes an integer input n. Inside the function, a local variable m is initialized to 3. The program should print the value of m before and after each recursive call. The input integer n is obtained from the user in the main function.

Here is a step-by-step guide to solve this problem:

First, you need to create a main function where you will get the input from the user.
Inside the main function, call the recursive function with the input integer.
Now, create the recursive function. Inside this function, initialize a local variable m to 3.
Print the value of m and the current call number before making the recursive call.
Make the recursive call with n-1 if n is greater than 0.
After the recursive call, print the value of m and the current call number again.

Here is a simple implementation in C++:

#include <iostream>
using namespace std;

void recursiveFunc(int n) {
    auto m = 3;
    cout << "Before call(" << n << "): " << m << endl;
    if(n > 0) {
        recursiveFunc(n-1);
    }
    cout << "After return(" << n << "): " << m << endl;
}

int main() {
    int n;
    cin >> n;
    recursiveFunc(n);
    return 0;
}

This program will print the value of m before and after each recursive call from n to 0. The value of m will always be 3 because it is a local variable and gets reinitialized in each function call.

This problem has been solved

Solution 2

The output should print the value of the variable m before and after each recursive call from n to 0. The format for before call should be: "Before call(x): m" where x is the number of the particular call. The format for after call should be: "After return(x): m" where x is the number of the particular call.

The constraints for the problem are that the input integer n should be between 1 and 10 inclusive.

Here is a step by step guide to solve the problem:

Write the main function that takes an integer input from the user.
Inside the main function, call the recursive function with the input integer.
Inside the recursive function, initialize a local variable m to 3.
Print the value of m and the number of the call before the recursive call.
Make the recursive call with the number of the call decremented by 1.
Print the value of m and the number of the call after the recursive call.
The base case for the recursion should be when the number of the call is 0. In this case, just return without making a recursive call.
Compile and run the program to check if it works as expected.

This problem has been solved

Solution 3

The problem is asking to write a program that uses a recursive function. The function is called with an integer input n. Inside the function, a local variable m is initialized to 3. The program should print the value of m before and after each recursive call. The input integer n is obtained from the user in the main function.

Here is a step-by-step guide on how to solve this problem:

First, you need to create a main function that gets an integer input from the user.
Inside the main function, call the recursive function with the input integer.
Now, create the recursive function. This function should take an integer as an input.
Inside the recursive function, initialize a local variable m to 3.
Print the value of m and the input integer in the format "Before call(x): m", where x is the input integer.
Now, check if the input integer is greater than 0. If it is, call the recursive function with the input integer decreased by 1.
After the recursive call, print the value of m and the input integer in the format "After return(x): m", where x is the input integer.
Finally, return from the recursive function.

Remember, the recursive function will call itself until the input integer is 0. At each call, it will print the value of m before and after the call.

This problem has been solved

Similar Questions

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