A man covers a distance on a bike. Had he moved 3kmph faster he would have taken 40 minutes less. If he had moved 2 km/h slower,he would have taken 40 minutes more. Find the distance covered by him.Question 1Answera.40 kmb.37kmc.26kmd.15km
Question
A man covers a distance on a bike. Had he moved 3kmph faster he would have taken 40 minutes less. If he had moved 2 km/h slower,he would have taken 40 minutes more. Find the distance covered by him.Question 1Answera.40 kmb.37kmc.26kmd.15km
Solution
Let's denote the distance as D (in km), the original speed as S (in km/h), and the time as T (in hours).
From the problem, we know that:
-
D = S * T
-
D = (S + 3) * (T - 40/60)
-
D = (S - 2) * (T + 40/60)
We can solve these equations step by step:
First, we equate equations (2) and (3) because they both equal to D:
(S + 3) * (T - 40/60) = (S - 2) * (T + 40/60)
Solving this equation, we get S = 20 km/h.
Substitute S = 20 km/h into equation (1), we get:
D = 20 * T
Substitute S = 20 km/h into equation (2), we get:
D = (20 + 3) * (T - 40/60)
Solving these two equations, we get T = 2 hours.
Finally, substitute S = 20 km/h and T = 2 hours into equation (1), we get:
D = 20 * 2 = 40 km.
So, the answer is a. 40 km.
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