Assuming that all variables are non-zero, simplify $$(2y2z0x3​)−4 using positive indices.

The expression you provided seems to have a typo. It's not clear what "2y2z0x3​" means.

If you meant $(2y^2z^0x^3)^{-4}$, then we can simplify it as follows:

Step 1: Recognize that any number or variable raised to the power of 0 is 1. So, z^0 = 1.

Step 2: Substitute z^0 = 1 into the expression, we get $(2y^2*1*x^3)^{-4}$, which simplifies to $(2y^2x^3)^{-4}$.

Step 3: Apply the rule (abc)^n = a^n * b^n * c^n, we get $2^{-4}*(y^2)^{-4}*(x^3)^{-4}$.

Step 4: Apply the rule (a^n)^m = a^(n*m), we get $2^{-4}*y^{-8}*x^{-12}$.

Step 5: Recognize that a^(-n) = 1/a^n, we get $1/2^4 * 1/y^8 * 1/x^{12}$.

Step 6: Simplify the expression, we get $1/16y^8x^{12}$.

So, $(2y^2z^0x^3)^{-4}$ simplifies to $1/16y^8x^{12}$.