To calculate the probability that only one person is killed by the disease in the current month, we need to use the average number of deaths per month, which is 3.

The probability of an event occurring can be calculated using the Poisson distribution formula, which is given by:

P(x; λ) = (e^(-λ) * λ^x) / x!

Where:
P(x; λ) is the probability of x events occurring,
e is the base of the natural logarithm (approximately 2.71828),
λ is the average number of events per interval (in this case, per month),
x is the number of events we are interested in (in this case, 1),
and x! is the factorial of x.

Plugging in the values, we have:
P(1; 3) = (e^(-3) * 3^1) / 1!

Calculating this expression, we find:
P(1; 3) ≈ 0.149

Therefore, the probability that only one person is killed by the disease in the current month is approximately 0.149.

So, the correct answer is d. 0.15.

Question

To calculate the probability that only one person is killed by the disease in the current month, we need to use the average number of deaths per month, which is 3.

The probability of an event occurring can be calculated using the Poisson distribution formula, which is given by:

P(x; λ) = (e^(-λ) * λ^x) / x!

Where:
P(x; λ) is the probability of x events occurring,
e is the base of the natural logarithm (approximately 2.71828),
λ is the average number of events per interval (in this case, per month),
x is the number of events we are interested in (in this case, 1),
and x! is the factorial of x.

Plugging in the values, we have:
P(1; 3) = (e^(-3) * 3^1) / 1!

Calculating this expression, we find:
P(1; 3) ≈ 0.149

Therefore, the probability that only one person is killed by the disease in the current month is approximately 0.149.

So, the correct answer is d. 0.15.

Knowee AI · Accepted Answer

To calculate the probability that only one person is killed by the disease in the current month, we need to use the average number of deaths per month, which is 3.

The probability of an event occurring can be calculated using the Poisson distribution formula, which is given by:

P(x; λ) = (e^(-λ) * λ^x) / x!

Where:
P(x; λ) is the probability of x events occurring,
e is the base of the natural logarithm (approximately 2.71828),
λ is the average number of events per interval (in this case, per month),
x is the number of events we are interested in (in this case, 1),
and x! is the factorial of x.

Plugging in the values, we have:
P(1; 3) = (e^(-3) * 3^1) / 1!

Calculating this expression, we find:
P(1; 3) ≈ 0.149

Therefore, the probability that only one person is killed by the disease in the current month is approximately 0.149.

So, the correct answer is d. 0.15.

On an average a disease kills 3 people each month in a city. What is the probability that only one person is killedby this disease in current month?Select one:a.0b.1c.0.25d.0.15

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