particle is moving with the given data. Find the position of the particle.a(t) = t2 − 9t + 5,    s(0) = 0,    s(1) = 20

A particle is moving with the given data. Find the position of the particle.a(t) = t2 − 7t + 6,    s(0) = 0,    s(1) = 20s(t) =

The position of a particle related to time is given by x = ( 5 t 2 − 4 t + 5 ) m . The magnitude of velocity of the particle at t = 2 s will be :

The position of a particle is defined by the equation s = 0.13t3 + t2 - 3t + 2, where s is in metres and t is in seconds. This equation is valid for the time range t=0 to t=5 seconds. Determine the following:(a) the velocity of the particle at t=1.25 seconds, v = Answer m/s(b) the acceleration of the particle at t=1.25 seconds, a = Answer m/s2

The position of a particle moving along the x-axis is given by x = a (t – 1) + b(t – 1) where a and b are constant, then :

The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.a(t) = 2t + 2,    v(0) = −15,    0 ≤ t ≤ 5(a) Find the velocity at time t.v(t) = t2+2t−15 m/s(b) Find the distance traveled during the given time interval.