You are riding on a large carousel at an amusement park and you are enjoying the moving scenery as the carousel spins about its center of rotation. The ride comes to an end and the carousel gradually slows to a stop. Why does it take so long for the carousel to stop rotating?1 pointThe spinning carousel carries a large amount of angular momentum and the angular impulse needed to remove that angular momentum with a reasonable torque requires a long time.The spinning carousel has a large angular velocity and changing a large angular velocity requires a long time.The spinning carousel has a large rotational mass and changing a large rotational mass requires a long time.The spinning carousel has a large angular impulse and changing a large angular impulse requires a long time.

Question 7A "lazy susan" is a disk-shaped rotating platform that a restaurant places at the center of a large dining table. Dishes of food are placed on the lazy susan and diners can rotate the lazy susan by hand to bring various dishes closer to them. A large torque exerted for a short time makes the motionless platform begin rotating rapidly, but that dangerous technique risks tipping over some of the food dishes. How can you make the same motionless platform and dishes begin rotating just as rapidly, but with a smaller, safer torque?1 pointDo the same angular impulse as the dangerous technique, but by exerting a smaller torque for a smaller time.Do the same angular impulse as the dangerous technique, but by exerting the smaller torque for a larger rotational mass.Do the same angular impulse as the dangerous technique, but by exerting the smaller torque for a smaller rotational mass.Do the same angular impulse as the dangerous technique, but by exerting a smaller torque for a longer time.

A uniform square plate is placed on a horizontal floor. When it is given an angular velocity o about a vertical axis through one of its corners as shown in figure-I, it takes time t1 to come to a complete stop. Now the same square plate is given the same angular velocity to rotate about another vertical axis through its centre as shown in figure-II. How long will it take to come to a complete stop now?

If you push a shopping cart in a supermarket carpark, and then let go, why does it eventually stop?Report an ErrorBecause friction acts as an unbalanced force to slow it down.Because the forces on it are balanced.Because there are no forces acting on it.Because the pushing force acts as an unbalanced force on the shopping cart.

A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 226 kg. A small boy of mass m = 47 kg runs tangentially to the merry-go-round at a speed of v = 2.1 m/s, and jumps on. Part (a) Calculate the moment of inertia of the merry-go-round, in kg ⋅ m2. Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry go round? Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy is at the center of the merry go round? Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off?

A Ferris wheel does one complete revolution every 55 hourshours. Express this as a rate of revolutions per minute. Remember to round your answer to 44 decimal place, and to include appropriate units.