The sides of a rectangle are x cm and 2x +1cm. therefore it's perimeter P is Blank 1 Question 3 and it's area A is Blank 2 Question 3 .If the rectangle is used for the base of a box of height 3 cm the volume V of the box is Blank 3 Question 3 .P = 6x +2 cm P = 3x+1cm P=6x+2 cm squared A= x(2x+1) cm squared A= x(2x+1) cm V= 3x(2x+1) cm cubed V= 3x(2x+1) cm squared V= 3x +(2x+1) cm cubed
Question
The sides of a rectangle are x cm and 2x +1cm. therefore it's perimeter P is Blank 1 Question 3 and it's area A is Blank 2 Question 3 .If the rectangle is used for the base of a box of height 3 cm the volume V of the box is Blank 3 Question 3 .P = 6x +2 cm P = 3x+1cm P=6x+2 cm squared A= x(2x+1) cm squared A= x(2x+1) cm V= 3x(2x+1) cm cubed V= 3x(2x+1) cm squared V= 3x +(2x+1) cm cubed
Solution
The sides of a rectangle are given as x cm and 2x + 1 cm.
-
The perimeter (P) of a rectangle is calculated as the sum of all its sides. Therefore, P = 2*(length + breadth) = 2*(x + 2x + 1) = 2*(3x + 1) = 6x + 2 cm.
-
The area (A) of a rectangle is calculated as the product of its length and breadth. Therefore, A = length * breadth = x * (2x + 1) = 2x^2 + x cm squared.
-
If the rectangle is used as the base of a box with a height of 3 cm, the volume (V) of the box is calculated as the product of the length, breadth, and height. Therefore, V = length * breadth * height = x * (2x + 1) * 3 = 6x^2 + 3x cm cubed.
So, the correct answers are: P = 6x + 2 cm, A = 2x^2 + x cm squared, and V = 6x^2 + 3x cm cubed.
Similar Questions
Two rectangular boxes are similar.One box is larger by a scale factor of 2.The smaller box has dimensions 1 metre, 2 metres and 3 metres.Question promptWhat is the volume of the larger box?Question response areaSelect one option6 m312 m324 m348 m3
Q.1. The length of a cuboidal box made of coloured paper is three units greater than the width, and its height is two units less than the width, if width is taken as x, answer the following questions. i) Select the polynomial that represents volume of the box*1 point4x² + 2x + 46x² + 4x-12x^3+x^2-6x5x^2 + 3x -12
Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have.(a) Draw several diagrams to illustrate the situation, some short boxes with large bases and some tall boxes with small bases. Find the volumes of several such boxes.(b) Draw a diagram illustrating the general situation. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.(c) Write an expression for the volume V in terms of both x and y.V = x(3−2x)(3−2x) (d) Use the given information to write an equation that relates the variables x and y.y=3−2x (e) Use part (d) to write the volume as a function of only x.V(x) = x(3−2x)(3−2x) (f) Finish solving the problem by finding the largest volume that such a box can have.V = ft3
A box with an open top is to be constructed from a rectangular piece of cardboard with dimensions 18 in. by 30 in. by cutting out equal squares of side x at each corner and then folding up the sides as shown in the figure. Express the volume V of the box as a function of x.A rectangular shaped object is shown. The longer sides are horizontal and labeled with a length of 30. The shorter sides are vertical and labeled with a length of 18. The rectangle is shaded green except for 4 white squares. One square is located at each of the four corners of the rectangle and each square has side length labeled x. A second image is also included of what the box will look like after the corners are removed. It has a rectangular bottom, 4 folded up sides, and no top. An unlabeled box with an open top is shown.V(x) =
A rectangular box has a volume of (x³ + 5x² – 12x – 36) cm³, length of (x + 6) cm and width of (x + 2) cm. What is its height?Select one:a. (x + 3) cmb. (x - 3) cmc. (x + 4) cmd. (x - 4) cm
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.