Determine the y-intercept of the following equation.left bracket, minus, x, plus, 4, right bracket, left bracket, x, plus, 5, right bracket, equals, y(−x+4)(x+5)=yAnswerMultiple Choice Answersleft bracket, 20, comma, 0, right bracket(20,0)left bracket, 0, comma, minus, 20, right bracket(0,−20)left bracket, minus, 4, comma, 0, right bracket, and , left bracket, minus, 5, comma, 0, right bracket(−4,0) and (−5,0)left bracket, 4, comma, 0, right bracket, and , left bracket, minus, 5, comma, 0, right bracket(4,0) and (−5,0)left bracket, 0, comma, 20, right bracket(0,20)left bracket, 0, comma, 4, right bracket, and , left bracket, 0, comma, minus, 5, right bracket(0,4) and (0,−5)

Determine the x-intercepts of the following equation.left bracket, x, minus, 4, right bracket, left bracket, x, minus, 3, right bracket, equals, y(x−4)(x−3)=yAnswerMultiple Choice Answersleft bracket, 12, comma, 0, right bracket(12,0)left bracket, 0, comma, 12, right bracket(0,12)left bracket, 4, comma, 0, right bracket, and , left bracket, minus, 3, comma, 0, right bracket(4,0) and (−3,0)left bracket, 0, comma, 4, right bracket, and , left bracket, 0, comma, 3, right bracket(0,4) and (0,3)left bracket, 4, comma, 0, right bracket, and , left bracket, 3, comma, 0, right bracket(4,0) and (3,0)left bracket, 0, comma, minus, 12, right bracket(0,−12)

Find the y-coordinate of the y-intercept of the polynomial function defined below.f, of, x, equals, left bracket, x, plus, 3, right bracket, left bracket, 3, x, squared, minus, 5, right bracket, left bracket, x, plus, 4, right bracketf(x)=(x+3)(3x 2 −5)(x+4)

Find the x-intercept and y-intercept of the line.=+5x4y−20x-intercept: y-intercept:

Let’s try another that we need to factor.Problemy=x2−5x−14𝑦=𝑥2−5𝑥−14 SolutionList out the factors of −14−14:−1−1 and 141411 and 22 and −2−2 and Which of these pairs add up to −5−5? and Now we’ll write this in factored form:y=(x+𝑦=(𝑥+ )(x−)(𝑥− ))To find the zeros/solutions/x𝑥-intercepts, set each factor equal to 00 and solve for x𝑥.x+𝑥+ =0=0 and x−𝑥− =0=0x=𝑥= and x=𝑥= Our two solutions are (( ,, )) and (( ,, )) (Enter from least to greatest.)We can now use these to find the vertex. Remember the x𝑥-value of the vertex, as well as the axis of symmetry, is halfway between the two solutions.−2+72=52=2.5−2+72=52=2.5x=2.5𝑥=2.5 is our axis of symmetry. We’ll substitute this value into our original equation to find the y𝑦-value of the vertex.y=(𝑦=( )2−5()2−5( )−14)−14y=6.25−12.5−14𝑦=6.25−12.5−14y=−20.25𝑦=−20.25The vertex is (( ,, )).Finally, state the domain and range.Domain: All real numbers (as with all quadratic functions)Range: y≥𝑦≥ CheckQuestion 3

What is the y-intercept of the polynomial f, of, xf(x) defined below? Write the y-value only.f, of, x, equals, minus, 10, x, cubed, minus, 4, x, plus, 3, x, squared, minus, x, to the power 6 , minus, 5f(x)=−10x 3 −4x+3x 2 −x 6 −5