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Statement-I: The gas liberated on warming a salt with dil H2SO4, turns a piece of paper dipped in lead acetate into black, it is a confirmatory test for sulphide ion.Statement-II: In statement-I the colour of paper turns black because of formation of lead sulphite. In the light of the above statements, choose the most appropriate answer from the options given below:

Question

Statement-I: The gas liberated on warming a salt with dil H2SO4, turns a piece of paper dipped in lead acetate into black, it is a confirmatory test for sulphide ion.Statement-II: In statement-I the colour of paper turns black because of formation of lead sulphite. In the light of the above statements, choose the most appropriate answer from the options given below:

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Solution

The statement-I is correct. When a salt is warmed with dilute H2SO4, and the gas liberated turns a piece of paper dipped in lead acetate black, it is indeed a confirmatory test for the presence of sulphide ions. This is because sulphide ions react with lead acetate to form lead sulphide, which is black.

However, statement-II is incorrect. The black color is not due to the formation of lead sulphite, but rather due to the formation of lead sulphide (PbS). Therefore, the correct answer would be that statement-I is true, but statement-II is false.

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