12345678910111213141516171819#include <stdio.h> void calc(double *result, double a, double b) { *result = (a * a) + (2 * a * b) + (b * b); } int main() { double res; calc(&res, 3.0, 4.0); printf("%.2lf", res); return 0; }
Question
12345678910111213141516171819#include <stdio.h> void calc(double *result, double a, double b) { *result = (a * a) + (2 * a * b) + (b * b); } int main() { double res; calc(&res, 3.0, 4.0); printf("%.2lf", res); return 0; }
Solution
The code you've posted is written in C language. It's a simple program that calculates the result of the equation (a^2) + (2ab) + (b^2) where a and b are inputs to the function calc().
Here's a step-by-step explanation:
-
The function
calc()is declared, which takes three parameters: a pointer to a doubleresult, and two double valuesaandb. -
Inside the
calc()function, the equation (a^2) + (2ab) + (b^2) is calculated and the result is stored in the memory location pointed to byresult. -
In the
main()function, a double variableresis declared. -
The
calc()function is called with the address ofres(&res), and two double values 3.0 and 4.0. -
The result of the calculation is stored in
res. -
The value of
resis printed to the console with a precision of 2 decimal places usingprintf(). -
The program returns 0 and ends.
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