A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are 19.6 m/s and 35m/s respectively. The horizontal range is:
Question
A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are 19.6 m/s and 35m/s respectively. The horizontal range is:
Solution
The horizontal range (R) of a projectile can be calculated using the formula:
R = (Vx * Vy) / g
where:
- Vx is the horizontal velocity component,
- Vy is the vertical velocity component, and
- g is the acceleration due to gravity.
Given that Vx = 19.6 m/s, Vy = 35 m/s, and g = 9.8 m/s², we can substitute these values into the formula:
R = (19.6 m/s * 35 m/s) / 9.8 m/s²
Solving this gives:
R = 70 m
Therefore, the horizontal range of the projectile is 70 meters.
Similar Questions
The equation of the projectile is y=20x−54x2 m.𝑦=20𝑥-54𝑥2 m. The horizontal range is
A projectile is aimed at a mark on a horizontal plane through the point of projection and falls 6 m short when its elevation is 30∘ but overshoot the mark by 9 m when its elevation is 45∘. The angle of elevation of projectile to hit the target on the horizontal plane
A projectile is projected at 30∘ from horizontal with initial velocity 40 ms−1. The velocity of the projectile at t=2 s from the start will be: (Given g=10 m/s2 )
A projectile is fired horizontally from a gun that is 45.0 mabove flat ground, emerging from the gun with a speed of250 m/s. (a) How long does the projectile remain in the air?(b) At what horizontal distance from the firing point does itstrike the ground? (c) What is the magnitude of the verticalcomponent of its velocity as it strikes the ground?
For general projectile motion, the horizontal component of a projectile's velocity
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.