A pair of linear equations which has a unique solution x = 2, y = -3 is:a.x + y = -1; 2x – 3y = -5b.2x + 5y = -11; 4x + 10y = -22c.2x – y = 1; 3x + 2y = 0d.x – 5y – 14 = 0; 5x – y – 13 = 0

To find out which pair of linear equations has a unique solution x = 2, y = -3, we need to substitute these values into each pair of equations and see which one holds true.

a. x + y = -1; 2x – 3y = -5 Substituting x = 2 and y = -3, we get: 2 - 3 = -1 (True) 22 - 3(-3) = 4 + 9 = 13 ≠ -5 (False)

b. 2x + 5y = -11; 4x + 10y = -22 Substituting x = 2 and y = -3, we get: 22 + 5(-3) = 4 - 15 = -11 (True) 42 + 10(-3) = 8 - 30 = -22 (True)

c. 2x – y = 1; 3x + 2y = 0 Substituting x = 2 and y = -3, we get: 22 - (-3) = 4 + 3 = 7 ≠ 1 (False) 32 + 2*(-3) = 6 - 6 = 0 (True)

d. x – 5y – 14 = 0; 5x – y – 13 = 0 Substituting x = 2 and y = -3, we get: 2 - 5*(-3) - 14 = 2 + 15 - 14 = 3 ≠ 0 (False) 5*2 - (-3) - 13 = 10 + 3 - 13 = 0 (True)

So, the pair of linear equations which has a unique solution x = 2, y = -3 is option b. 2x + 5y = -11; 4x + 10y = -22.