Here are the first five terms of an arithmetic sequence.8 15 22 29 36Work out the sum of all the terms from the 50th term to the 100th term inclusive.
Question
Here are the first five terms of an arithmetic sequence.8 15 22 29 36Work out the sum of all the terms from the 50th term to the 100th term inclusive.
Solution
Sure, let's solve this step by step.
Step 1: Find the common difference (d) In an arithmetic sequence, the difference between any two consecutive terms is constant. This is called the common difference. In this case, the common difference is 15 - 8 = 7.
Step 2: Find the first term (a) The first term in the sequence is 8.
Step 3: Find the 50th term (a50) The nth term of an arithmetic sequence can be found using the formula a + (n - 1)d. So, the 50th term would be a + (50 - 1)d = 8 + (49 * 7) = 351.
Step 4: Find the 100th term (a100) Similarly, the 100th term would be a + (100 - 1)d = 8 + (99 * 7) = 701.
Step 5: Find the sum of terms from the 50th to the 100th term The sum of an arithmetic series can be found using the formula n/2 * (a + l) where n is the number of terms, a is the first term, and l is the last term. Here, n = 100 - 50 + 1 = 51 (we add 1 because both 50th and 100th terms are inclusive), a = a50 = 351 and l = a100 = 701.
So, the sum would be 51/2 * (351 + 701) = 25.5 * 1052 = 26826.
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