At STP, how many moles of gas occupy a room with a volume of 6.0 m3? [1 m3 = 1000 L]

At Standard Temperature and Pressure (STP), one mole of any gas occupies 22.4 liters.

Step 1: Convert the volume from m3 to L. 1 m3 = 1000 L, so 6.0 m3 = 6.0 * 1000 = 6000 L.

Step 2: Calculate the number of moles. We know that 1 mole of gas occupies 22.4 L at STP. So, the number of moles (n) can be calculated using the formula:

n = V / Vm

where: V is the volume of the gas, and Vm is the molar volume of the gas (22.4 L at STP).

So, n = 6000 L / 22.4 L/mole = 267.86 moles.

Therefore, at STP, 267.86 moles of gas occupy a room with a volume of 6.0 m3.