Given below are two statements labelled as Assertion (A) and Reason (R)Assertion (A): The empirical mass of Ethene is half of its molecular mass.Reason (R ) : The empirical formula represents the simplest whole number ratio of various atomspresent in a compoundSelect the most appropriate answer from the options given below:a) Both A and R are true and R is the correct explanation of Ab) Both A and R are true but R is not the correct explanation of A.c) A is true but R is false.d) A is false but R is true.
Question
Given below are two statements labelled as Assertion (A) and Reason (R)Assertion (A): The empirical mass of Ethene is half of its molecular mass.Reason (R ) : The empirical formula represents the simplest whole number ratio of various atomspresent in a compoundSelect the most appropriate answer from the options given below:a) Both A and R are true and R is the correct explanation of Ab) Both A and R are true but R is not the correct explanation of A.c) A is true but R is false.d) A is false but R is true.
Solution
The given statements are:
Assertion (A): The empirical mass of Ethene is half of its molecular mass. Reason (R): The empirical formula represents the simplest whole number ratio of various atoms present in a compound.
To determine the most appropriate answer, we need to evaluate the truthfulness of both statements.
Statement A states that the empirical mass of Ethene is half of its molecular mass. This means that the empirical formula of Ethene represents the simplest whole number ratio of atoms present in the compound. To verify this, we can calculate the empirical mass and molecular mass of Ethene.
The empirical formula of Ethene is CH2, which means it contains one carbon atom and two hydrogen atoms. The atomic mass of carbon is 12.01 g/mol, and the atomic mass of hydrogen is 1.01 g/mol. Therefore, the empirical mass of Ethene can be calculated as follows:
Empirical mass = (1 * atomic mass of carbon) + (2 * atomic mass of hydrogen) Empirical mass = (1 * 12.01 g/mol) + (2 * 1.01 g/mol) Empirical mass = 12.01 g/mol + 2.02 g/mol Empirical mass = 14.03 g/mol
Now, let's calculate the molecular mass of Ethene. The molecular formula of Ethene is also C2H4, which means it contains two carbon atoms and four hydrogen atoms. Using the same atomic masses as before, we can calculate the molecular mass as follows:
Molecular mass = (2 * atomic mass of carbon) + (4 * atomic mass of hydrogen) Molecular mass = (2 * 12.01 g/mol) + (4 * 1.01 g/mol) Molecular mass = 24.02 g/mol + 4.04 g/mol Molecular mass = 28.06 g/mol
Comparing the empirical mass (14.03 g/mol) with the molecular mass (28.06 g/mol), we can see that the empirical mass is indeed half of the molecular mass. Therefore, Assertion (A) is true.
Statement R states that the empirical formula represents the simplest whole number ratio of atoms present in a compound. This is a general definition of an empirical formula and is true for all compounds. Therefore, Reason (R) is also true.
Based on the evaluation of both statements, we can conclude that both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A). Therefore, the most appropriate answer is option (a) Both A and R are true and R is the correct explanation of A.
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