If H2SO4 follows Lewis octet rule then formal charge on sulphur isA+1 B+2 C0 D2
Question
If H2SO4 follows Lewis octet rule then formal charge on sulphur isA+1 B+2 C0 D2
Solution
To calculate the formal charge of an atom in a molecule, the formula used is:
Formal charge = [# of valence electrons on atom] - [non-bonding valence electrons + 1/2 bonding electrons]
In the case of sulfur in H2SO4:
- Sulfur is in group 6 on the periodic table, so it has 6 valence electrons.
- In H2SO4, sulfur is bonded to four oxygen atoms and does not have any non-bonding electrons.
- Each bond consists of 2 electrons, so sulfur has 4*2 = 8 bonding electrons.
Substituting these values into the formula gives:
Formal charge = 6 - (0 + 1/2 * 8) = 6 - 4 = +2
So, the formal charge on sulfur in H2SO4 is +2. Therefore, the correct answer is B+2.
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