The energy needed to increase the temperature of 1.2 kg of oil by 40 °C was 100.8 kJ.Calculate the specific heat capacity of this oil._________ J/kg°CYou do not need to give units in your answer.
Question
The energy needed to increase the temperature of 1.2 kg of oil by 40 °C was 100.8 kJ.Calculate the specific heat capacity of this oil._________ J/kg°CYou do not need to give units in your answer.
Solution
The specific heat capacity (c) can be calculated using the formula:
Q = mcΔT
where: Q = heat energy absorbed or released (in joules or J) m = mass of the substance (in kilograms or kg) c = specific heat capacity (in joules per kilogram per degree Celsius or J/kg°C) ΔT = change in temperature (in degrees Celsius or °C)
In this case, we are given: Q = 100.8 kJ = 100.8 x 10^3 J (since 1 kJ = 10^3 J) m = 1.2 kg ΔT = 40 °C
We are asked to find c. Rearranging the formula for c gives:
c = Q / (mΔT)
Substituting the given values into this formula gives:
c = (100.8 x 10^3 J) / (1.2 kg x 40 °C) = 2100 J/kg°C
So, the specific heat capacity of the oil is 2100 J/kg°C.
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