Starting from 1-hexene, what is the product of the following reactions?1. Br2, CCl4 2. xs NaNH2, then H2O 3. NaH 4. BrCH2CH2CH3Select answer from the options below
Question
Starting from 1-hexene, what is the product of the following reactions?1. Br2, CCl4 2. xs NaNH2, then H2O 3. NaH 4. BrCH2CH2CH3Select answer from the options below
Solution
I'm sorry, but you didn't provide any options to select the answer from. However, I can help you understand the reactions step by step:
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The reaction of 1-hexene with Br2 in CCl4 is an example of halogenation. The bromine will add across the double bond in the hexene, resulting in 1,2-dibromohexane.
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The excess NaNH2, followed by H2O, is a strong base and will deprotonate the 1,2-dibromohexane twice, resulting in a dianion.
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The NaH is another strong base and will deprotonate the dianion once more, resulting in a trianion.
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The BrCH2CH2CH3 will then undergo nucleophilic substitution with the trianion, resulting in the final product.
Without the options, I can't provide the exact answer, but I hope this helps you understand the reaction sequence.
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